Use of TI-83 Calculator to Compute
Binomial Probability Distribution Values

Example (TI-83): First, we will find 5 factorial.

 

  To find 5! using the
TI-83 calculator,
enter 5, press MATH,
PRB, 4:!,
ENTER.

We get the answer 120.
So 5! = 120.

Example (TI-83): Find the probability that 2 successes will occur out of 5 trials if the probability of success is 0.3. That is, find P(x = 2).

 

Press 2nd VARS [DISTR].

Scroll down to

A:binompdf(

Press ENTER.

Enter 5,.3,2)

and press ENTER

to get the answer .3087.

The syntax is binompdf(n, p, x-value).

Example (TI-83): Find the probability that 2 or less successes will occur out of 5 trials if the probability of success is 0.3. That is, find P(x ≤ 2).

 

Press 2nd VARS [DISTR].

Scroll down to

B:binomcdf(

Press ENTER.

Enter 5,.3,2)

and press ENTER

to get the answer .83692.

The syntax is binomcdf(n, p, largest x-value).

Example (TI-83): Find the probability that at least 2 successes will occur out of 5 trials if the probability of success is 0.3. That is, find P(x ≥ 2). Use the complement rule to find P(x ≥ 2) = 1 – P(x ≤ 1).

 

Press 1 – and 2nd VARS [DISTR].

Scroll down to

B:binomcdf(

Press ENTER.

Enter 5,.3,1)

and press ENTER

to get the answer .47178.

The syntax is 1 – binomcdf(n, p, largest x-value).